why did you remove the Powered By Logo/Text link? It is something that cannot be removed or modified.
looking at the source of that page I see this:
<tr>
<td width="100%" colspan="2">
<table border="0" bordercolor="#000000" align="left" cellPadding="4" cellSpacing="0" width="100%">
<tr><td width="33%" align="left" valign="top">
<font face="Verdana, Arial, Helvetica" size="1" color="white">This page took 0.55 seconds to load</font>
</td><td align="center" width="33%">
<!-- Place code here -->
<!-- Place code here -->
</td><td align="right" valign="top" width="33%"><font face="Verdana, Arial, Helvetica" size="1">
</td>
</tr>
</table>
</td>
</tr>
</table>
</font>
</body>
</html>
You completely removed the following code:
'## START - REMOVAL, MODIFICATION OR CIRCUMVENTING THIS CODE WILL VIOLATE THE SNITZ FORUMS 2000 LICENSE AGREEMENT
Response.Write "<a href=""http://forum.snitz.com"" target=""_blank"" tabindex=""-1""><acronym title=""Powered By: " & strVersion & """>"
if strShowImagePoweredBy = "1" then
Response.Write getCurrentIcon("logo_powered_by.gif||","Powered By: " & strVersion,"")
else
Response.Write "Snitz Forums 2000"
end if
Response.Write "</acronym></a></font></td>" & vbNewline
'## END - REMOVAL, MODIFICATION OR CIRCUMVENTING THIS CODE WILL VIOLATE THE SNITZ FORUMS 2000 LICENSE AGREEMENT
did you not read where it very clearly says REMOVAL, MODIFICATION OR CIRCUMVENTING THIS CODE WILL VIOLATE THE SNITZ FORUMS 2000 LICENSE AGREEMENT ?