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GoodMorningSky
Junior Member
122 Posts |
 Posted - 04 April 2005 : 03:36:14
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How to show property of custom control in Property window?
I make Validator : System.Web.UI.WebControls.CustomValidator
class.
and defined ValidationType property which is type of ValidateType.
I want to make the proerty is shown with Extended dropdown menu in properties window of Design mode.
I added the validator control to toolbox and droped to WebForm in design mode but, property window doesn't show the property!
I did following but, it doesn't show.
How can I do it?
using System;
using System.Web.UI;
using System.ComponentModel;
namespace TestControls
{
/// <summary>
/// Summary description for Validator.
/// </summary>
[DefaultProperty("ValidationType")]
public class Validator : System.Web.UI.WebControls.CustomValidator
{
public Validator()
{
}
private ValidateType _validateType;
[Bindable(true), Browsable(true),
Category("Appearance"),
TypeConverter(typeof(ValidateType))]
public ValidateType ValidationType
{
set
{
_validateType = value;
switch(_validateType)
{
case ValidateType.Email:
this.ClientValidationFunction="OnValidate_Email";
this.ErrorMessage = "Test Error";
break;
}
}
}
}
}
using System;
namespace TestControls
{
public enum ValidateType
{
Email = 1,
Phone = 2,
}
}
[/CODE] |
Software Engineer.
MCSD.NET, SCWCD |
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Topic Locked
