Azzur
Starting Member
13 Posts |
Posted - 23 October 2003 : 10:51:41
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Hi, I am trying to systematize the mod LINK to make to work him/it with the database sql. I/you/they have succeeded in making to work different parts of the mod but I find some problem with the page of the search, in fact when insrerisco a term the page underlines me this error: Type of error: ADODB.Recordset (0x800A0CB3) Il set di record corrente non supporta i segnalibri. Potrebbe trattarsi di una limitazione del provider o del tipo di cursore selezionato. /forum/links_search.asp, this is the piece of code where the error is signalled me: <% if show = "10" then strSQL = "select * from links where Keyword like'%" & search & "%' or Description like '%" & search & "%' order by link_ID" 'build string for connection my database file is link.mdb in store in the same folder of this file. Dim iPageSize Dim iPageCount Dim iPageCurrent Dim strOrderBy Dim strSQL Dim objPagingConn Dim objPagingRS Dim iRecordsShown Dim I iPageSize = 10 'set page size If Request.QueryString("page") = "" Then iPageCurrent = 1 Else iPageCurrent = CInt(Request.QueryString("page")) End If If Request.QueryString("order") = "" Then strOrderBy = "link_id" Else strOrderBy = Request.QueryString("order") End If Set objPagingRS = Server.CreateObject("ADODB.Recordset") objPagingRS.PageSize = iPageSize objPagingRS.CacheSize = iPageSize objPagingRS.Open strSQL, my_Conn, adOpenStatic, adLockReadOnly, adCmdText reccount = objPagingRS.recordcount iPageCount = objPagingRS.PageCount If iPageCurrent > iPageCount Then iPageCurrent = iPageCount If iPageCurrent < 1 Then iPageCurrent = 1 If iPageCount = 0 Then Response.Write "<tr><center><td width=100% colspan=2 align=center><font face=Verdana color=red size=2><b><br><br>nulla č stato trovato</b></font><br><br><font face=Verdana size=1><a href=media.asp>Effettua nuova ricerca</a></center></font></td></tr></table><br>" Else ##########This is The Incriminated Line ######objPagingRS.AbsolutePage = iPageCurrent %> The error that is pointed out me by Ie is to the line that I have pointed out Here you Above With The ###### From thing can depend the error?? I don't succeed in understanding!! |
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